Question

quantas moleculas existem em 80 g de gelo seco (co2 solido) ?

Answer 1

massa molar = 44g/mol

44g ------------------ 6*10²³ moleculas
80 g -----------------   x

x*44 = 80 * 6 * 10²³
x = 480 * 10²³ / 44

x = 10,9*10²³
x =1, 09 *10²⁴ moleculas

Answer 2

MM = 44g/mol

44g ---- 6,02x10²³
80g --- y

y = 1,09x10²⁴