Question

Quantas e quais raízes reais tem a equação x elevado a 2 menos 3X - 10 = 0

Answer 1

X²-3X-10=0

∆= b²-4ac

∆= 9+40

∆= 49

X= -b+-✓∆

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2a

X= 3+-7

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2

X1= 5

X2= -2

TEM DUAS RAÍZES REAIS!

S={5,-2}

Answer 2

Olá...

$x^2-3x-10=0\\\\Coeficientes:\;a=1,\;b=-3\;e\;c=-10\\\\\Delta=b^2-4ac\\\Delta=-3^2-4\cdot1\cdot(-10)\\\Delta=9+40\\\Delta=49\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{3\pm\sqrt{49}}{2\cdot1}\\\\x=\dfrac{3\pm7}{2}\\\\x_1=\dfrac{3+7}{2}=\dfrac{10}{2}=5\\\\x_2=\dfrac{3-7}{2}=\dfrac{-4}{2}=-2$

Espero ter ajudado.