Question

Quando misturamos 2,0 kg de água (calor específico sensível = 1,0 cal/g°C) a 50°C com 2,0 kg de água a 10°C, obtemos 4,0 kg de água

Answer 1

Espero ter ajudado.

$2000\cdot 1\cdot (Tf - 50) + 2000\cdot 1 \cdot (Tf-10) = 0\\\\2000\left(Tf-50\right)+2000\left(Tf-10\right)=0\\\\4000Tf-120000=0\\\\4000Tf-120000+120000=0+120000\\\\4000Tf=120000\\\\\boxed{Tf=\frac{120000}{4000}=30 }$

30°C