Question

Quando a = 10, b = 8 e c = 21, calcule:

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Answer 1

Resposta:

a) 7

b) 11

Explicação passo-a-passo:

a) $\sqrt[3]{7.(2.10+8+21)}$

$\sqrt[3]{7.(20 +8+21)\\}$

$\sqrt[3]{7.49}$

$\sqrt[3]{343}$

7

b) $\sqrt{bc + 1}$ - $\sqrt[3]{b}$

$\sqrt{8.21 + 1}$ - $\sqrt[3]{8}$

$\sqrt{169}$ - 2

13 - 2

11

Answer 2

a) ³√ 7×(2×10 + 8 + 21 )=

³√ 7 × 49=

³√ 343 = 7

b) √ 8 × 21 + 1 - ³√ 8=

√ 169 - ³√ 8=

13 - 2=

11