Question

Qual valor de x, no triangulo abaixo​

Answer 1

x² = 3²+8² -2.3.8.(cos60)

x² = 9+64 -48(1/2)

x² = 73 - 24

x² = 49

x = √49

x = 7

Answer 2

$\mathsf{{x}^{2}={8}^{2}+{3}^{2}-2.8.3.\cos(60^{\circ})}$

$\mathsf{{x}^{2}=64+9-2.24.\dfrac{1}{2}}$

$\mathsf{{x}^{2}=49}\\\mathsf{x=\sqrt{49}}$

$\large\boxed{\boxed{\boxed{\mathsf{x=7}}}}$