Question

Qual será a soma dos termos 15 da PG (3,6,12,...)​

Answer 1

$> resolucao \\ \\ \geqslant progressao \: geometrica \\ \\ q = \frac{a2}{a1} \\ q = \frac{6}{3} \\ q = 2 \\ \\ \geqslant a \: soma \: dos \: 15 \: termos \: da \: pg \\ \\ sn = \frac{a1(q {}^{n} - 1)}{q - 1} \\ \\ sn = \frac{3(2 {}^{15} - 1)}{2 - 1} \\ \\ sn = \frac{3(32768 - 1)}{1} \\ \\ sn = \frac{3 \times 32767}{1} \\ \\ sn = 3 \times 32767 \\ \\ sn = 98301 \\ \\ > < > < > < > < > < > < > >$