Question

Qual será a conta de 10x-5(1+x)=3(2x-2)-20

Answer 1

Resposta:

10x−5⋅(x+1)−{3⋅(2x−2)−20}=0

10x−(5x+5)−{(6x−6)−20}=0

(5x−5)−{6x−26}=0

−x+21=0

(−1)⋅x+(21)=0

x=−(21)−1

x=21

Espero ter ajudado