Question

qual são as raizes da equação x2-3x-4=0..

Answer 1

Resolução da questão pela fórmula de Bhaskara, veja:

$\mathsf{x^2-3x-4=0}\\\\\\\\ \mathsf{\Delta = b^2-4~\cdot~a~\cdot~c}\\\\\ \mathsf{\Delta=(-3)^2-4~\cdot~1~\cdot~(-4)}\\\\\ \mathsf{\Delta=9+16}\\\\\ \mathsf{\Delta=25}\\\\\\ \mathsf{x =-b~\pm~ \dfrac{\sqrt\Delta}{2~\cdot~a}}}\\\\\\ \mathsf{x = 3~\pm~\dfrac{\sqrt{25}}{2~\cdot~1}}\\\\\\ \mathsf{x = 3~\pm~\dfrac{5}{2}}\\\\\\ \mathsf{x' = \dfrac{3+5}{2}}\\\\\ \mathsf{x' = \dfrac{8}{2}}\\\\\ \mathsf{x' =4}\\\\\\ \mathsf{x'' = \dfrac{3-5}{2}}\\\\\\ \mathsf{x'' = \dfrac{-2}{2}}~\therefore~\mathsf{x'' =-1}}$

Para concluir temos que as raízes da equação são:

$\large{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\mathsf{x'=4~~\textsf{e}~~x''=-1.}}}}}}}}}}}}}}}}}}}}}$

Espero que te ajude. :-).

Dúvidas? Comente.

Answer 2

Resposta:

nao seiii ainnnn nobru apelao

Explicação passo-a-passo:

da coraçao ai