Question

Qual são as coordenadas do vértice da função f(x)= -x²+4x​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{f(x) = -x^2 + 4x}$

$\mathsf{\Delta = b^2 - 4.a.c}$

$\mathsf{\Delta = 4^2 - 4.(-1).(0)}$

$\mathsf{\Delta =16 - 0}$

$\mathsf{\Delta =16}$

$\mathsf{V = \{-\dfrac{b}{2a};-\dfrac{\Delta}{4a}\}}$

$\mathsf{V = \{\dfrac{-4}{-2};\dfrac{-16}{-4}\}}$

$\boxed{\boxed{\mathsf{V = \{\:2\:;\:4\:\}}}}$

Answer 2

Resposta:

Explicação passo a passo:

\mathsf{f(x) = -x^2 + 4x}f(x)=−x

2

+4x

\mathsf{\Delta = b^2 - 4.a.c}Δ=b

2

−4.a.c

\mathsf{\Delta = 4^2 - 4.(-1).(0)}Δ=4

2

−4.(−1).(0)

\mathsf{\Delta =16 - 0}Δ=16−0

\mathsf{\Delta =16}Δ=16

\mathsf{V = \{-\dfrac{b}{2a};-\dfrac{\Delta}{4a}\}}V={−

2a

b

;−

4a

Δ

}

\mathsf{V = \{\dfrac{-4}{-2};\dfrac{-16}{-4}\}}V={

−2

−4

;

−4

−16

}

\boxed{\boxed{\mathsf{V = \{\:2\:;\:4\:\}}}}

V={2;4}