Question

Qual resultado?
2-{\frac{1}{2} ÷4-6^{0} +[5+(2^{2}÷0,333...)]}=

Answer 1

$=2-| \frac{1}{2} \div 4 - {6}^{0} + |5 + ({2}^{2} + 0.33)||$

$= 2 - | \frac{1}{2} \div 4 - 1 + |5 +( 4 \div 0.33)|$

$= 2 - | \frac{1}{2} \div 4 - 1 + | 5 + 12.12 | |$

$= 2 - | 0.5 \div 4 - 1 + 17.12 |$

$= 2 - |0.125 - 1 + 17.12|$

$= 2 - 16.245$

$= 14.245$