Question

qual o volume do cilindro cuja altura é 5 m e o raio é 4m. ​

Answer 1

• O volume desse cilindro é igual a 251,20 m².

Para calcular o volume de um cilindro, devemos utilizar a seguinte fórmula: $\large\displaystyle\begin{aligned} V = \pi\cdot r^2\cdot h\end{aligned}$. Onde r é o raio e h é a altura. Logo:

$\large\displaystyle\begin{aligned} V = \pi\cdot r^2\cdot h\end{aligned}$

$\large\displaystyle\begin{aligned} V = 3,14\cdot 4^2m\cdot 5m\end{aligned}$

$\large\displaystyle\begin{aligned} V = 3,14\cdot 16m\cdot 5m\end{aligned}$

$\large\displaystyle\begin{aligned} V = 3,14\cdot 80m^2\end{aligned}$

$\large\displaystyle\text{ \begin{aligned} \therefore \boxed{\boxed{\green{V = 251,20\ m^2}}}\end{aligned} }$

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Answer 2

Resposta correta:

$~~{\because~~\boxed{\boxed{\begin{array}{lr}\red{~V = 251,2m^{2}~}\end{array}}}}$

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$~~~~~~\huge\mid{\boxed{\bf{\blue{Matem\acute{a}tica}}}\mid}$

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Solução passo a passo

Como a base é um círculo, onde $r$ é o raio da base. Isso dá: $\displaystyle{V = \pi \times r^{2} \times h}$

Sendo:

• $\displaystyle{\text{Raio}~R = 4m;}$
• $\displaystyle{\text{Altura}~H = 5m;}$
• $\displaystyle{\pi~= 3,14.}$

$\large\underline{ \overline{\boxed{\begin{array}{clr}\\ \displaystyle{ 3,14 \times 4^{2}m \times 5m }\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \end{array}}}}$

Para começar vamos resolver a potência$~4^{2}m$

$\large\gray{~~~~\downarrow}~~~\displaystyle\begin{aligned}3,14 \times 16m \times 5m\end{aligned}\left\{\begin{array}{ll}\displaystyle{4^{2}m}\\ \\ 4m \times 4m \\ \\ ~~\displaystyle{= 16m ~~} \\ \end{array}\right.$

Agora e apenas calcula a multiplicação $3,14 \times 16m \times 5m$

$\large\gray{~~~~\downarrow}~~~\displaystyle\begin{aligned}251,2m^{2}\end{aligned}\left\{\begin{array}{ll}\displaystyle{3,14 \times 16m \times 5m}\\ \\ 16m \times 5m = 80m^{2} \\ \\ 3,14 \times 80m^{2}\\ \\ ~~\displaystyle{= 251,2m^{2} ~~} \\ \end{array}\right.$

Solução:

$~~{\therefore~~\boxed{\boxed{\begin{array}{lr}\red{~V = 251,2m^{2}~}\end{array}}}}$

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$\: \: \: \text{\underline{Att.}}$

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${~~\vdots~~~\large\boxed {\boxed{15:06h}~28.09.21}}$

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