Question

qual o vértice da parábola y = 2x² - 4x + 5

Answer 1

2x^2-4x+5=0
delta=b^2-4ac
delta=(-4)^2-4.2.5
delta=16-40
delta=-24
xv=-b/2a
xv=-(-4)/2.2
xv=4/4
xv=1
yv=-delta/4a
yv=-(-24)/4.2
yv=24/8
yv=3
(1,3)