qual o valor para x na equação?
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SheldonCooper89:
Para quem não esta entendendo quando temos raiz, o índice vira denominador.
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![a^{x}=a^{y}~~~\therefore~~~\boxed{\boxed{x=y}}~~~~~(sendo~a\ \textgreater \ 0~e~\neq1)\\\\\sqrt[y]{a^{x}}\rightleftharpoons a^{(x/y)}\\\\\dfrac{1}{a^{x}}\rightleftharpoons a^{-x}\\\\(a^{x})^{y}\rightleftharpoons a^{xy} a^{x}=a^{y}~~~\therefore~~~\boxed{\boxed{x=y}}~~~~~(sendo~a\ \textgreater \ 0~e~\neq1)\\\\\sqrt[y]{a^{x}}\rightleftharpoons a^{(x/y)}\\\\\dfrac{1}{a^{x}}\rightleftharpoons a^{-x}\\\\(a^{x})^{y}\rightleftharpoons a^{xy}](https://tex.z-dn.net/?f=a%5E%7Bx%7D%3Da%5E%7By%7D%7E%7E%7E%5Ctherefore%7E%7E%7E%5Cboxed%7B%5Cboxed%7Bx%3Dy%7D%7D%7E%7E%7E%7E%7E%28sendo%7Ea%5C+%5Ctextgreater+%5C+0%7Ee%7E%5Cneq1%29%5C%5C%5C%5C%5Csqrt%5By%5D%7Ba%5E%7Bx%7D%7D%5Crightleftharpoons+a%5E%7B%28x%2Fy%29%7D%5C%5C%5C%5C%5Cdfrac%7B1%7D%7Ba%5E%7Bx%7D%7D%5Crightleftharpoons+a%5E%7B-x%7D%5C%5C%5C%5C%28a%5E%7Bx%7D%29%5E%7By%7D%5Crightleftharpoons+a%5E%7Bxy%7D)
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![(\sqrt[5]{3^{2}})^{x}=\frac{1}{81}\\\\\\(3^{(2/5)})^{x}=\frac{1}{3^{4}}\\\\\\3^{(2/5)\cdot x}=3^{-4} (\sqrt[5]{3^{2}})^{x}=\frac{1}{81}\\\\\\(3^{(2/5)})^{x}=\frac{1}{3^{4}}\\\\\\3^{(2/5)\cdot x}=3^{-4}](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7B3%5E%7B2%7D%7D%29%5E%7Bx%7D%3D%5Cfrac%7B1%7D%7B81%7D%5C%5C%5C%5C%5C%5C%283%5E%7B%282%2F5%29%7D%29%5E%7Bx%7D%3D%5Cfrac%7B1%7D%7B3%5E%7B4%7D%7D%5C%5C%5C%5C%5C%5C3%5E%7B%282%2F5%29%5Ccdot+x%7D%3D3%5E%7B-4%7D)
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