Question

qual o valor dos zeros da seginte funcão do 2°?
f(x) = x² – 2x - 3​

Answer 1

Função Quadrática

• Coeficientes:

$\boxed{ \begin{array}{lr} \large \sf \: a = 1 \\ \large \sf \:b = - 2 \\ \large \sf \:c = - 3 \end{array}}$

• Discriminante:

$\boxed{ \begin{array}{lr} \\ \large \sf \: \Delta = {b}^{2} - 4ac \\ \\\large \sf \: \Delta = {( - 2)}^{2} - 4 \cdot1 \cdot - 3 \\ \\\large \sf \: \Delta = 4 + 12 \\ \\ \red{\large \sf \:\Delta = 16} \\ \: \end{array}}$

• Bhaskara:

$\boxed{ \begin{array}{lr} \\ \large \sf \: x = \dfrac{ - b \: \pm \: \sqrt{\Delta} }{2.a} \\ \\ \\ \large \sf \: x = \dfrac{ - ( - 2) \: \pm \: \sqrt{16} }{2.1} \\ \\ \\ \large \sf \: x = \dfrac{ 2 \: \pm \: 4 }{2} \\ \: \end{array}}$

• Raízes:

$\large \boxed{ \boxed{ \large \sf \: x_{1} = \dfrac{2 + 4}{2} = \boxed{ \sf \red{3}}}} \\ \\ \large \boxed{ \boxed{ \large \sf \: x_{2} = \dfrac{2 - 4}{2} = \boxed{ \sf \red{ - 1}}}}$

➡️ Resposta:

• $\huge \boxed{ \boxed{ \huge \sf \: S = \{3, - 1 \}}}$

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