Question

Qual o valor do limite

Answer 1

Resposta:

Explicação passo-a-passo:

$\lim_{x \to \22} \frac{x^{2}-5x+6 }{x-2}= \lim_{x \to \22}\frac{(x-2)(x-3)}{x-2}= \lim_{x\to \22} (x-3)=2-3=-1$

Answer 2

Lim. (x²-5x+6)/(x-2)

x→2

x²-5x+6 =x²-2x-3x+6=x(x-2)-3(x-2)

x²-5x+6=(x-2)(x-3)

Lim. (x²-5x+6)/(x-2)

x→2

= Lim. (x-2)(x-3)/(x-2)

x→2

= Lim (x-3) = 2-3 =-1

x→2