Question

qual o valor de x? $\sqrt[5]{2 ^{x} }= \frac{1}{32}$

Answer 1

(2^x)^(1/5) = 1/32

(2^x)^(1/5) = 2^(-5)

2^(x/5) = 2^(-5)

x/5 = -5

x = -25

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07/07/2016
Sepauto - SSRC
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Answer 2

vamos colocar todo mundo na base 2:

$2^{ \frac{x}{5} } = \frac{1}{ 2^{5} }$
$2^{ \frac{x}{5} } = 2^{-5}$
agora reslvemos:

x/5=-5
x=-25