Question

Qual o valor de x no triangulo abaixo, sabendo -se que sen 45° = 0,7, cos 45° = 0,7 e tan 45° = 1,0
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Answer 1

$\Large\boxed{\begin{array}{l}\sf tg(45^\circ)=\dfrac{9}{x}\\\\\sf 1=\dfrac{9}{x}\\\\\sf x=9\end{array}}$