Question

qual o valor de x na igualdade ?(abram a imagem) URGENTEMENTE

Answer 1

Observe que

$\left (\dfrac{9}{4}\right )^{x+2}=\left (\dfrac{2}{3}\right )^{3x-31}\\\\\left (\dfrac{3}{2}\right )^{2x+4}=\left (\dfrac{2}{3}\right )^{3x-31}\\\\\left (\dfrac{3}{2}\right )^{2x+4}=\left (\dfrac{3}{2}\right )^{31-3x}\\\\\\2x+4=31-3x\Rightarrow 5x=27\Rightarrow x=\dfrac{27}{5}$

Answer 2

$({ \frac{3}{2} }^{2} ) ^{x + 2} = ( \frac{2}{3} ) ^{3 x - 31}$
$( \frac{3}{2} ) ^{2x + 4} = ( \frac{3}{2}) ^{ - 3x + 31}$
$2x + 4 = - 3x + 31$
$5x = 27$
$x = \frac{27}{5}$
resposta: letra e