Matemática, perguntado por schreinermatheus3, 5 meses atrás

Qual o valor de X na figura?
A) 2,2
B) 16,2
C) 18,2
D) 4,2
E) 1,8

Anexos:

Soluções para a tarefa

Respondido por EinsteindoYahoo
1

tan(60°)=AC/6  

AC=6 * tan(60°)

AC= 6 * (√3)

tan(45°)= AC/(x+6)

1 = AC/(x+6)

x+6= AC

x+6=6√3

x= 6√3-6

x = 4,39230

Respondido por ramalhoraquel36
1

Resposta:

tan(60°)=AC/6

tan(60°)=AC/6AC=6* tan(60°)

tan(60°)=AC/6AC=6* tan(60°)AC= 6* (√3)

tan(60°)=AC/6AC=6* tan(60°)AC= 6* (√3)1

tan(60°)=AC/6AC=6* tan(60°)AC= 6* (√3)15.0

tan(60°)=AC/6AC=6* tan(60°)AC= 6* (√3)15.0tan(45°)= AC/(x+6)

tan(60°)=AC/6AC=6* tan(60°)AC= 6* (√3)15.0tan(45°)= AC/(x+6)1= AC/(x+6)

tan(60°)=AC/6AC=6* tan(60°)AC= 6* (√3)15.0tan(45°)= AC/(x+6)1= AC/(x+6)x+6= AC

tan(60°)=AC/6AC=6* tan(60°)AC= 6* (√3)15.0tan(45°)= AC/(x+6)1= AC/(x+6)x+6= ACx+6=6√3

tan(60°)=AC/6AC=6* tan(60°)AC= 6* (√3)15.0tan(45°)= AC/(x+6)1= AC/(x+6)x+6= ACx+6=6√3x= 6√3-6

tan(60°)=AC/6AC=6* tan(60°)AC= 6* (√3)15.0tan(45°)= AC/(x+6)1= AC/(x+6)x+6= ACx+6=6√3x= 6√3-6x = 4,39230

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