Question

Qual o valor de x??????​

Answer 1

Resposta:

Explicação passo-a-passo:

Como são triângulos retângulos, basta usar o teorema de Pitágoras.

a)

$(2x)^{2}=(3\sqrt{3})^{2}+x^{2}\\\\4x^{2}=9.3+x^{2}\\\\4x^{2}-x^{2}=27\\\\3x^{2}=27\\\\x^{2}=\frac{27}{3}\\\\x^{2}=9\\\\x=\sqrt{9}\\\\x=3$

b)

$(x+5)^{2}=6^{2}+(x+3)^{2}\\\\x^{2}+10x+25=36+x^{2}+6x+9\\\\x^{2}-x^{2}+10x-6x=45-25\\\\4x=20\\\\x=\frac{20}{4}\\\\x=5$

Answer 2

Resposta:

a)

(2x)^{2}=(3\sqrt{3})^{2}+x^{2}\\\\4x^{2}=9.3+x^{2}\\\\4x^{2}-x^{2}=27\\\\3x^{2}=27\\\\x^{2}=\frac{27}{3}\\\\x^{2}=9\\\\x=\sqrt{9}\\\\x=3

b)

(x+5)^{2}=6^{2}+(x+3)^{2}\\\\x^{2}+10x+25=36+x^{2}+6x+9\\\\x^{2}-x^{2}+10x-6x=45-25\\\\4x=20\\\\x=\frac{20}{4}\\\\x=5

Explicação passo-a-passo: