Question

qual o valor de X:

1) x²- 7x+10=0
2) x²- 6x+9=0

Answer 1

1) x^2-7x+10=0
delta=b^2-4.a.c
delta=(-7)^2-4.1.10
delta=49-40
delta=9
x=-b-/+ raiz de delta/2a
x=-(-7)-3/2.1
x=7-3/2
x=4/2
x=2
x=-(-7)+3/2.1
x=7+3/2
x=10/2
x=5
2) x^2-6x+9=0
delta=b^2-4.a.c
delta=(-6)^2-4.1.9
delta=36-36
delta=0
x=-b-/+ raiz de delta/2a
x=-(-6)-0/2.1
x=6-0/2
x=6/2
x=3