Question

Qual o valor de f (1-i) na função f (z)=z2 -2z+2

Answer 1

$f(z)=z^{2}-2z+2\\f(1-i)=(1-i)^{2}-2(1-i)+2\\f(1-i)=(1^{2}-2*1*i+i^{2}) - 2 + 2i + 2\\f(1-i)=(1-2i+[-1])+2i\\f(1-i)=-2i+2i\\f(1-i)=0$