Question

qual o valor de 330K para F​

Answer 1

$\frac{TF-32}{9}=\frac{TK-273}{5}\\\frac{TF-32}{9}=\frac{330-273}{5}\\\frac{TF-32}{9}=\frac{57}{5}$

5·(TF-32)=9·57

5TF-160=513

5TF=513+160

5TF=673

TF=$\frac{673}{5}$

TF=134°F