Question

qual o valor de √1+√289/√21+√12
me ajudem pfv

Answer 1

Resposta:

Se for (√1+√289)/(√21 +121)

√289 = 17

√1 = 1

= (1+17)/(√21 +121)

=18/(√21 +121)

=18(√21 -121)/[(√21 +121)(√21 -121)]

=18(√21 -121)/(√21² -121²)

=[18√21 - 18*121]/(21-14641)

=(18√21 -2178)/(-14620)

=2178/14620 - 18√21/14620 ≈ 0,143331986