Question

qual o valor das equações?


(x-3)(x+1)= 0

(2x+2)elevado a dois = 0

4x ao quadrado - 3= 0

Answer 1

A) (x-3)(x+1)= 0
x-3 = 0
x = 3
ou
x+1=0
x = -1;

B)
(2x+2)² = 0
4x²+8x+4=0
x²+2x+1=0
Δ=4-4=0
x= -2/2 
x= -1;

4x² - 3= 0
4x² = 3
x² = 3/4
x = √3/√4
x = √3/2;

Answer 2

(x-3)(x+1)= 0
x² +x -3x -3 =0
x² - 2x - 3 =0
Δ= 4+12 = 16
√Δ= √16 = 4
x' = (2+4)/2 = 3
x"= (2-4)/2 = -1

(2x+2)² =0
(2x)² + 2.2x.2 + 2² =
 4x² + 8x + 4 = 0 (:4)
 x² + 2x + 1 = 0
Δ= 2² - 4 = 4-4=0



x = (-2+0)/2 = -1


4x² - 3 = 0
4x² = 3
x² = 3/4
x = √3/4 ----> x = √3/2