Question

Qual o valor da questão
$\frac{2}{ \sqrt[3]{2} } \times 4( \frac{1}{3}) \times 2 { - }^{2}$
​

Answer 1

Resposta:

$\frac{\sqrt[3]{4}}{3}$

Explicação passo a passo:

$\frac{2}{\sqrt[3]{2} }$ = $\frac{2}{\sqrt[3]{2} }$ · $\frac{\sqrt[3]{2^{2}}}{\sqrt[3]{2^{2}}}$

$\frac{2}{\sqrt[3]{2} }$ = $\frac{2 . \sqrt[3]{2^{2}} }{\sqrt[3]{2^{1} . 2^{2}}}$

$\frac{2}{\sqrt[3]{2} }$ =  $\frac{2\sqrt[3]{2^{2}} }{\sqrt[3]{2^{3}} }$

$\frac{2}{\sqrt[3]{2} }$ = $\frac{2\sqrt[3]{2^{2}} }{2}$

$\frac{2}{\sqrt[3]{2} }$ = $\sqrt[3]{2^{2}}$

4 . $(\frac{1}{3})$ = $\frac{4}{3}$

$2^{-2}$ = $(\frac{1}{2} )^{2}$

$2^{-2}$ = $\frac{1}{4}$

$\frac{2}{\sqrt[3]{2} }$ . 4 . $(\frac{1}{3})$ .  $2^{-2}$ = $\sqrt[3]{2^{2}}$ · $\frac{4}{3}$ · $\frac{1}{4}$

$\frac{2}{\sqrt[3]{2} }$ . 4 . $(\frac{1}{3})$ .  $2^{-2}$ = $\sqrt[3]{2^{2}}$ · $\frac{1}{3}$

$\frac{2}{\sqrt[3]{2} }$ . 4 . $(\frac{1}{3})$ .  $2^{-2}$ = $\frac{\sqrt[3]{4}}{3}$

Valor procurado: $\frac{\sqrt[3]{4}}{3}$