Question

qual o valor da expressão: log2(32.64)

Answer 1

log2(32.64)≈5,0286

e)8^x=1/8
   8^x=8^-1
      x=-1

Answer 2

$\log_2(32.64)=\log_232+\log_264=\log_2 2^{5} +\log_22^{6}=5\log_2 2 +6\log_22$$=5.1+6.1=5+6=11$

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$8^{x} = \dfrac{1}{8}$ ⇒ $8^{x} = 8^{-1}$ ⇒ $x=-1$