Matemática, perguntado por hannasilva001, 6 meses atrás

Qual o valor da expressão abaixo? (-2)¹.{(-3)²-2³+[(√25-8²:4²)-√9:3⁰]}³​

Soluções para a tarefa

Respondido por justforthebois123
2

Resposta:

2

Explicação passo a passo:

\left(-2\right)^1\left(\left(-3\right)^2-2^3+\left(\left(\sqrt{25}-\frac{8^2}{4^2}\right)-\frac{\sqrt{9}}{3^0}\right)\right)\right^3

=\left(-2\right)^1\left(\left(-3\right)^2+\sqrt{25}-2^3-\frac{\sqrt{9}}{1}-\frac{8^2}{4^2}\right)\right^3

=\left(-2\right)\left(\left(-3\right)^2+\sqrt{25}-2^3-\frac{\sqrt{9}}{1}-\frac{8^2}{4^2}\right)\right^3

=-2\left(\left(-3\right)^2-2^3+\sqrt{25}-\frac{8^2}{4^2}-\frac{\sqrt{9}}{1}\right)\right^3

=-2\left(\left9-2^3+\sqrt{25}-\frac{8^2}{4^2}-\frac{\sqrt{9}}{1}\right)\right^3

=-2\left(\left9-8+\sqrt{25}-\frac{8^2}{4^2}-\frac{\sqrt{9}}{1}\right)\right^3

=-2\left(\left9-8+5-\frac{8^2}{4^2}-\frac{\sqrt{9}}{1}\right)\right^3

=-2\left(\left9-8+5-\frac{64}{16}-\frac{\sqrt{9}}{1}\right)\right^3

=-2\left(\left9-8+5-\frac{64}{16}-\frac{3}{1}\right)\right^3

=-2\left(\left9-8+5-4-\frac{3}{1}\right)\right^3

=-2\left(\left9-8+5-4-3\right)\right^3

=-2\left(\left1+5-4-3\right)\right^3

=-2\left(\left6-4-3\right)\right^3

=-2\left(\left2-3\right)\right^3

=-2\left(\left -1 \right)\right^3

=-2\left(-1\right)

=2\cdot 1\right

=2

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