qual o valor da expressão a + b /1 - a.b para a = - 1 e b = 3
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Boa noite Fabricio!
Solução!
![a=-1\\\\\
b=3\\\\\
\dfrac{a+b}{1-a.b} \\\\\\\\
\dfrac{-1+3}{1-(-1).(3)}\\\\\\\
\dfrac{-1+3}{1-(-3)}\\\\\\\
\dfrac{-1+3}{1+3}\\\\\\\
\frac{2}{4}\\\\\\\
\frac{1}{2}](https://tex.z-dn.net/?f=a%3D-1%5C%5C%5C%5C%5C%0Ab%3D3%5C%5C%5C%5C%5C+%0A%0A%0A%5Cdfrac%7Ba%2Bb%7D%7B1-a.b%7D+%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cdfrac%7B-1%2B3%7D%7B1-%28-1%29.%283%29%7D%5C%5C%5C%5C%5C%5C%5C%0A%5Cdfrac%7B-1%2B3%7D%7B1-%28-3%29%7D%5C%5C%5C%5C%5C%5C%5C%0A%5Cdfrac%7B-1%2B3%7D%7B1%2B3%7D%5C%5C%5C%5C%5C%5C%5C%0A+%5Cfrac%7B2%7D%7B4%7D%5C%5C%5C%5C%5C%5C%5C%0A+%5Cfrac%7B1%7D%7B2%7D++ "a=-1\\\\\
b=3\\\\\
\dfrac{a+b}{1-a.b} \\\\\\\\
\dfrac{-1+3}{1-(-1).(3)}\\\\\\\
\dfrac{-1+3}{1-(-3)}\\\\\\\
\dfrac{-1+3}{1+3}\\\\\\\
\frac{2}{4}\\\\\\\
\frac{1}{2}")
Boa noite!
Bons estudos!
Solução!
Boa noite!
Bons estudos!
Respondido por
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Basta substituir os valores indicados nas respectivas incógnitas:
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