Question

Qual o valor da área sombreada no gráfico?

Answer 1

$\displaystyle\mathsf{A=\int\limits_{-1}^{2}({x}^{2}+1)dx = \frac{1}{3} {x}^{3} + x \big |_{ - 1}^{2} }$

$\mathsf{A=\dfrac{1}{3}.{2}^{3}+2-(\dfrac{1}{3}{(-1)}^{3}-1)}\\\mathsf{A=\dfrac{8}{3}+2+\dfrac{1}{3}+1}$

$\mathsf{A=\dfrac{8+1}{3}+3=3+3}$

$\mathsf{A=6~u.a}$