Qual o sexto termo da PG (-240 , -120, -60 .......)?
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Boa noite Helder!
Solução!
Vamos determinar a razão da P.G.
![a1=-240\\\\\
a2=-120\\\\\
q= \dfrac{a2}{a1} \\\\\\
q= \dfrac{-120}{-240}\\\\\\\
q= \dfrac{1}{2}](https://tex.z-dn.net/?f=a1%3D-240%5C%5C%5C%5C%5C%0Aa2%3D-120%5C%5C%5C%5C%5C%0A%0Aq%3D+%5Cdfrac%7Ba2%7D%7Ba1%7D+%5C%5C%5C%5C%5C%5C%0Aq%3D+%5Cdfrac%7B-120%7D%7B-240%7D%5C%5C%5C%5C%5C%5C%5C%0Aq%3D+%5Cdfrac%7B1%7D%7B2%7D++ "a1=-240\\\\\
a2=-120\\\\\
q= \dfrac{a2}{a1} \\\\\\
q= \dfrac{-120}{-240}\\\\\\\
q= \dfrac{1}{2}")
Formula da P.G
Organizando os dados.
![a1=-240\\\\\\ q= \frac{1}{2}\\\\\\ n=6\\\\\\\\ an=-240. (\frac{1}{2}) ^{(6-1)}\\\\\\\
an=-240. (\dfrac{1}{2}) ^{5}\\\\\\\\
an=-240. (\dfrac{1}{32}) }\\\\\\\
an= \dfrac{-240}{32} }\\\\\\\\
Simplificando\\\\\
an=- \dfrac{15}{2}](https://tex.z-dn.net/?f=a1%3D-240%5C%5C%5C%5C%5C%5C+q%3D+%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5C%5C+n%3D6%5C%5C%5C%5C%5C%5C%5C%5C+an%3D-240.+%28%5Cfrac%7B1%7D%7B2%7D%29+%5E%7B%286-1%29%7D%5C%5C%5C%5C%5C%5C%5C%0Aan%3D-240.+%28%5Cdfrac%7B1%7D%7B2%7D%29+%5E%7B5%7D%5C%5C%5C%5C%5C%5C%5C%5C%0A+an%3D-240.+%28%5Cdfrac%7B1%7D%7B32%7D%29+%7D%5C%5C%5C%5C%5C%5C%5C%0Aan%3D+%5Cdfrac%7B-240%7D%7B32%7D+%7D%5C%5C%5C%5C%5C%5C%5C%5C%0ASimplificando%5C%5C%5C%5C%5C%0Aan%3D-+%5Cdfrac%7B15%7D%7B2%7D++++ "a1=-240\\\\\\ q= \frac{1}{2}\\\\\\ n=6\\\\\\\\ an=-240. (\frac{1}{2}) ^{(6-1)}\\\\\\\
an=-240. (\dfrac{1}{2}) ^{5}\\\\\\\\
an=-240. (\dfrac{1}{32}) }\\\\\\\
an= \dfrac{-240}{32} }\\\\\\\\
Simplificando\\\\\
an=- \dfrac{15}{2}")
Boa noite!
Bons estudos!
Solução!
Vamos determinar a razão da P.G.
Formula da P.G
Organizando os dados.
Boa noite!
Bons estudos!
heldernsjunior:
Obrigado tinha me esquecido de agradecer
Dê nada! Boa tarde!
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