Question

qual o sen, cos e tg de 1590°

Answer 1

$\Large\boxed{\begin{array}{l}\sf\, 1590^\circ|\underline{360^\circ}\\\sf\underline{\!\!\!\!-1440^\circ}~~4\\\sf~~150^\circ\\\sf 1590^\circ=4\cdot(360^\circ)+150^\circ\\\sf sen(1590^\circ)=sen(150^\circ)=sen(30^\circ)=\dfrac{1}{2}\\\\\sf cos(1590^\circ)=cos(150^\circ)=-cos(30^\circ)=-\dfrac{\sqrt{3}}{2}\\\\\sf tg(1590^\circ)=tg(150^\circ)=-tg(30^\circ)=-\dfrac{\sqrt{3}}{3}\end{array}}$