Question

Qual o resultado das expressões: A) √8+√8= B) √12-√12= C) √5•√5= D) √7•√8= E)1/3 + 1/6 = F) √20 : √10 = G) √9 : √3 = H) 2/3 - 1/3 = I) 7/6• 2/7 = J) 9/8 + 3/7 =

Answer 1

Explicação passo-a-passo:

a) $\sf \sqrt{8}+\sqrt{8}$

$\sf =2\sqrt{8}$

$\sf =2\cdot2\sqrt{2}$

$\sf =4\sqrt{2}$

b) $\sqrt{12}-\sqrt{12}$

$\sf =0$

c) $\sf \sqrt{5}\cdot\sqrt{5}$

$\sf =\sqrt{25}$

$\sf =5$

d) $\sf \sqrt{7}\cdot\sqrt{8}$

$\sf =\sqrt{7}\cdot2\sqrt{2}$

$\sf =2\sqrt{14}$

e) $\sf \dfrac{1}{3}+\dfrac{1}{6}$

$\sf =\dfrac{2+1}{6}$

$\sf =\dfrac{3}{6}$

$\sf =\dfrac{1}{2}$

f) $\sf \dfrac{\sqrt{20}}{\sqrt{10}}$

$\sf =\dfrac{\sqrt{10}\cdot\sqrt{2}}{\sqrt{10}}$

$\sf =\sqrt{2}$

g) $\sf \dfrac{\sqrt{9}}{\sqrt{3}}$

$\sf =\dfrac{\sqrt{3}\cdot\sqrt{3}}{\sqrt{3}}$

$\sf =\sqrt{3}$

h) $\sf \dfrac{2}{3}-\dfrac{1}{3}$

$\sf =\dfrac{2-1}{3}$

$\sf =\dfrac{1}{3}$

i) $\sf \dfrac{7}{6}\cdot\dfrac{2}{7}$

$\sf =\dfrac{14}{42}$

$\sf =\dfrac{1}{3}$

j) $\sf \dfrac{9}{8}+\dfrac{3}{7}$

$\sf =\dfrac{9\cdot7+3\cdot8}{56}$

$\sf =\dfrac{63+24}{56}$

$\sf =\dfrac{87}{56}$

Answer 2

Oie, Td Bom?!

A)

$= \sqrt{8} + \sqrt{8} \\ = 2 \sqrt{2} + 2 \sqrt{2} \\ = (2 + 2) \sqrt{2} \\ = 4 \sqrt{2}$

B)

$= \sqrt{12} - \sqrt{12} \\ = 0$

C)

$= \sqrt{5} \sqrt{5} \\ = \sqrt{25} \\ = \sqrt{5 {}^{2} } \\ = 5$

D)

$= \sqrt{7} \: . \: \sqrt{8} \\ = \sqrt{56} \\ = \sqrt{2 {}^{2} \: . \: 14} \\ = \sqrt{2 {}^{2} } \sqrt{14} \\ = 2 \sqrt{14}$

E)

$= \frac{1}{3} + \frac{1}{6} \\ \\ = \frac{2 + 1}{6} \\ \\ = \frac{3}{6} \\ \\ = \frac{3 \div 3}{6 \div 3} \\ \\ = \frac{1}{2}$

F)

$= \sqrt{20} \div \sqrt{10} \\ = \sqrt{20 \div 10} \\ = \sqrt{2}$

G)

$= \sqrt{9} \div \sqrt{3} \\ \\ = 3 \div \sqrt{3} \\ \\ = \frac{3}{ \sqrt{3} } \\ \\ = \frac{3}{ \sqrt{ 3 } } \: . \: \frac{ \sqrt{3} }{ \sqrt{3} } \\ \\ = \frac{3 \sqrt{3} }{ \sqrt{3} \sqrt{3} } \\ \\ = \frac{3 \sqrt{3} }{3} \\ \\ = \sqrt{3}$

H)

$= \frac{2}{3} - \frac{1}{3} \\ \\ = \frac{2 - 1}{3} \\ \\ = \frac{1}{3}$

I)

$= \frac{7}{6} \: . \: \frac{2}{7} \\ \\ = \frac{7 \div 7}{6} \: . \: \frac{2}{7 \div 7} \\ \\ = \frac{1}{6} \: . \: \frac{2}{1} \\ \\ = \frac{1}{6} \: . \: 2 \\ \\ = \frac{1}{6 \div 2} \: . \: 2 \div 2 \\ \\ = \frac{1}{3} \: . \: 1 \\ \\ = \frac{1}{3}$

J)

$= \frac{9}{8} + \frac{3}{7} \\ \\ = \frac{63 + 24}{56} \\ \\ = \frac{87}{56}$

Att. Makaveli1996