Question

qual o resultado da exploração
$\sqrt[10]{8} \div \sqrt[15]{ {2}^{3} }$
?
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Answer 1

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$\sf\sqrt[10]{8}\div\sqrt[15]{2^3}\\\sf\sqrt[15]{8}\div\sqrt[15]{8}\\\sf\sqrt[30]{8^3}\div\sqrt[30]{8^2}=\sqrt[30]{8^{3-2}} \\\sf\sqrt[30]{8}=\sqrt[30\div3]{2^{3\div3}}=\sqrt[10]{2}$

Answer 2

Oie, Td Bom?!

$= \sqrt[10]{8} \div \sqrt[15]{2 {}^{3} }$

$= \sqrt[30]{8 {}^{3} } \div \sqrt[30]{2 {}^{6} }$

$= \sqrt[30]{8 {}^{3} \div 2 {}^{6} }$

$= \sqrt[30]{(2 {}^{3} ) {}^{3} \div 2 {}^{6} }$

$= \sqrt[30]{2 {}^{9} \div 2 {}^{6} }$

$= \sqrt[30]{2 {}^{9 - 6} }$

$= \sqrt[30]{2 {}^{3} }$

$= \sqrt[30 \div 3]{2 {}^{3 \div 3} }$

$= \sqrt[10]{2 {}^{1} }$

$= \sqrt[10]{2}$

Att. Makaveli1996