Question

qual o resultado da equaçao 3y2+2y-1=0

Answer 1

3y2=3*y*2=3*2*y, então,
3y2+2y-1=0
6y+2y-1=0
8y-1=0
8y=1
y=1/8

Answer 2

3y² +2y -1 = 0
b²-4ac = delta
2² -4.3.(-1) = delta
4 +12 = 16
delta = 16

(-b +/- sqrt(delta))/2a    sqtr = raiz quadrada
(-2 +/- sqtr(16))/2.3
(-2 +/- 4)/6 =2/6 = {y1 , y2}

(-2 +4)/6 = 2/6 = 1/3
(-2 - 4)/6 = -6/6 = -1

y1 = 1/3
y2 = -1

3y² +2y -1 = 0

3(1/3)² + 2(1/3) -1 = 0
3(1/9) + 2/3 -1 = 0
3/9 + 2/3 -1 = 0
1/3 +2/3 -1 = 0
(1 + 2)/3 -1 = 0
3/3 -1 = 0
1 -1 = 0

3y² +2y -1 = 0
3(-1)² +2(-1) -1 = 0
3.1 -2 -1 = 0
3 -3 = 0