Question

qual o resultado da equação 1-(x+2)²=0 ?

Answer 1

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$1-(x+2)^2=0 \\ 1-( x^{2}+ 4x+4)=0 \\ 1- x^{2} -4x-4=0 \\ - x^{2} -4x-3=0 \\ x^{2} +4x+3=0 \\ \\ \Delta=b^2-4ac \\ \Delta=4^2-4(1)(3) \\ \Delta=16-12 \\ \Delta=4 \\ \\ x=- \frac{b\pm \sqrt{\Delta} }{2a} = \frac{-4\pm \sqrt{4} }{2} = \frac{-4\pm2}{2} \\ \\ x'= \frac{-4-2}{2} =- \frac{6}{2} =-3 \\ \\ x"= \frac{-4+2}{2} =- \frac{2}{2} =-1$