Question

Qual o resultado da conta: -x ao quadrado + 6x -5 =0?

Answer 1

Resposta:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~-x^{2}+6x-5=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=-1{;}~b=6~e~c=-5\\\\\Delta=(b)^{2}-4(a)(c)=(6)^{2}-4(-1)(-5)=36-(20)=16\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(6)-\sqrt{16}}{2(-1)}=\frac{-6-4}{-2}=\frac{-10}{-2}=5\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(6)+\sqrt{16}}{2(-1)}=\frac{-6+4}{-2}=\frac{-2}{-2}=1\\\\S=\{5,~1\}$