Question

qual o resultado
4×(x^2+2)=8×(x+1)

Answer 1

4*(x²+2)= 8*(x+1)
4x²+8= 8x+8
4x²-8x=8-8
4x²-8x=0
Δ= (-8)²-4*4*0
Δ= 64

$x= \frac{-(-8)+- \sqrt{64} }{2*4} = \frac{8+-8}{8} \\ \\ x'= \frac{8+8}{8}= \frac{16}{8}= 2 \\ \\ x''= \frac{8-8}{8}= \frac{0}{8}= 0$