Question

Qual o resultado ? ײ-5×+24=0

Answer 1

nos meus calculos deu:

delta= -71 (n tem raizes)

xv=5/2
yv=71/4

certo?

Answer 2

$x^2 - 5x + 24 = 0$

Resolvendo por Bháskara:


a=1, b=−5, c=24
Δ=b²−4ac
Δ=(−5)2−4*(1)*(24)
Δ=25−96
Δ= −71

Resolvendo para o conjunto dos números complexos (C)


$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ \\ x = \dfrac{-(-5) \pm \sqrt{-71}}{2*1} \\ \\ \\ x = \dfrac{5 \pm \sqrt{71} * i}{2} \\ \\ \\ x = \dfrac{5 \pm \sqrt{71} * i}{2} \\ \\ \\ x' = \dfrac{5 + \sqrt{71} * i}{2} \\ \\ \\ x'' = \dfrac{5 + \sqrt{71} * i}{2}$


S = {$\dfrac{5 + \sqrt{71} * i}{2}, \ \ \dfrac{5 - \sqrt{71} * i}{2}$}