Question

Qual o ponto de máximo da questão abaixo?
$y = - 6x ^{2} + 6x$

resposta com cálculos,obgd.​

Answer 1

$\Large\boxed{\begin{array}{l}\sf y=-6x^2+6x\\\sf \Delta=b^2-4ac\\\sf \Delta=6^2-4\cdot(-6)\cdot0\\\sf\Delta=36\\\sf x_V=-\dfrac{b}{2a}\\\\\sf x_V=-\dfrac{\backslash\!\!\!6}{2\cdot-\backslash\!\!\!6}=\dfrac{1}{2}\\\\\sf y_V=-\dfrac{\Delta}{4a}\\\\\sf y_V=-\dfrac{36}{4\cdot(-6)}=\dfrac{36\div12}{24\div12}\\\\\sf y_V=\dfrac{3}{2}\\\sf V\longrightarrow ponto~de~m\acute aximo\\\sf V\bigg(\dfrac{1}{2},\dfrac{3}{2}\bigg)\end{array}}$