Question

qual o número de moléculas existentes em 24g de C2H4O2

Answer 1

$\Large\boxed{\begin{array}{l}\sf m_{C_2H_4O_2}=2\cdot12+4\cdot1+2\cdot16\\\sf m_{C_2H_4O_2}=24+4+32=60\,g/mol\\\sf 60\,g\longrightarrow 6\cdot10^{23}\,mol\acute eculas\\\sf24\,g\longrightarrow x\\\sf 60x=24\cdot6\cdot10^{23}\\\\\sf x=\dfrac{24\cdot6\cdot10^{23}}{60}\\\\\sf x=\dfrac{\diagdown\!\!\!\!\!\!12\cdot12\cdot10^{23}}{\diagdown\!\!\!\!\!\!12\cdot5}\\\\\sf x=2,4\cdot10^{23}\,mol\acute eculas\end{array}}$