Question

qual o delta de: x elevado a 2 +4x-12=0

Answer 1

${x}^{2} + 4x - 12 = 0 \\ a = 1 \\ b =4 \\ c = - 12 \\ \\ delta = {b}^{2} - 4ac \\ {4 }^{2} - 4 \times 1 \times ( - 12) \\ 16 + 48 = 64 \\ \sqrt{64 } = 8$