Question

Qual o delta de :
-4x²+6x=0 ​

Answer 1

Resposta:

$-4x^2+6x=0\quad :\quad x=0,\:x=\frac{3}{2}$

Δ=b²- 4.a.c

$a=-4\\b=6\\c=0$

Δ=b²- 4.a.c

Δ=6²- 4.(-4).0

Δ=36