Question

Qual o 16 termo da PG ? (512, 256 ...)

Answer 1

an = a1.qⁿ⁻¹      → q = a2/a1 = 256/512 = 1/2
a16 = 512.(1/2)¹⁶⁻¹
a16 = 512.(2⁻¹)¹⁵
a16 = 512.2⁻¹⁵
a16 = 2⁸.2⁻¹⁵
a16 = 2⁻⁷
a16 = (1/2)⁷
a16 = 1/128