Question

Qual é o x¹ e o x² da expressão 9x²-12x+4=0? *​

Answer 1

Resposta:

9x² - 12x + 4 = 0

(A=9, B= -12, C=4)

∆= b² - 4ac

∆=(-12)² - 4 . 9 .4

∆=144 - 144

∆=0

x=-b ± √∆ / 2a

x= - (-12) ± √0 / 2 . 9

×= 12 ± 0 / 18

x'=

\frac{12 + 0}{18} = \frac{12}{18} = \frac{2}{3}

18

12+0

=

18

12

=

3

2

x''=

\frac{12 - 0}{18} = \frac{12}{18} = \frac{2}{3}

18

12−0

=

18

12

=

3

2

S=

\frac{2}{3}

3

2