Question

Qual é o valor maximo assumido pela função quadratica definida pela lei: y=-x elevado a 2+12x-20?

Answer 1

$\mathsf{y=-x^2+12x-20}\\\mathsf{a=-1~~~b=12~~~c=-20}$

$\mathsf{\Delta=b^2-4ac}\\\mathsf{\Delta=12^2-4.(-1).(-20)}\\\mathsf{\Delta=144-80}\\\mathsf{\Delta=64}$

O máximo da função ocorre no

$\mathsf{y_{V}}$

$\mathsf{y_{V}=-\dfrac{\Delta}{4a}}\\\mathsf{y_{V}=-\dfrac{64}{4.(-1)}=\dfrac{64}{4}=16}$