Question

qual e o valor de y=log na base4(log na base 3*9)+log base 3(log 1000)

Answer 1

log(3)9 = log(3) 3² = 2.log(3)3 = 2 . 1 = 2
log(4)2 = log(2²)2 = 1/2 x log(2)2 = 1/2 x 1 = 1/2
1/2 + 3 log 1000 = 
1/2 + 3 log 10³ =
1/2 + 3.3 =
1/2 + 9 =
1/2 + 18/2 = 19/2