Question

qual é o valor de x, sendo
$x = \sqrt{21 + \sqrt{13 + \sqrt{7 + \sqrt{4} } } }$
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Answer 1

$x=\sqrt{21+\sqrt{13+\sqrt{7+\sqrt{4}}}}\\\\\\x=\sqrt{21+\sqrt{13+\sqrt{7+2}}}\\\\\\x=\sqrt{21+\sqrt{13+\sqrt{9}}}\\\\\\x=\sqrt{21+\sqrt{13+3}}\\\\\\x=\sqrt{21+\sqrt{16}}\\\\\\x=\sqrt{21+4}\\\\\\x=\sqrt{25}\\\\\\\boxed{x=5}$

Answer 2

Olá !


$x = \sqrt{21 + \sqrt{13 + \sqrt{7 + \sqrt{4} } } } = > \sqrt{21 + \sqrt{13 + \sqrt{7 + \sqrt{4} } } } = > \\ \\ x = \sqrt{21 + \sqrt{13 + \sqrt{7 + 2} } } \\ \\ x = \sqrt{21 + \sqrt{13 + \sqrt{9} } } \\ \\ x = \sqrt{21 + \sqrt{13 + 3} } \\ \\ x = \sqrt{21 + \sqrt{16} } \\ \\ x = \sqrt{21 + 4} \\ \\ x = \sqrt{25} \\ \\ x = 5$


espero ter ajudado!

boa tarde!