Question

qual é o valor de n na equação (n+1)!/n!=68

Answer 1

           $\frac{(n+1)!}{n!} =68 \\ \\ \frac{(n+1)[(n+1)-1]!}{n!} =68 \\ \\ \frac{(n+1)(n+1-1)!}{n!} =68 \\ \\ \frac{(n+1)n!}{n!} =68 \\ \\ n+1=68 \\ \\ n= 68-1 \\ \\ n=67$