Question

Qual é o valor de a x b , sendo

Answer 1

$a=(\frac{1}{4})^{-2} +(\frac{1}{3})^{-2}\\ \\a=(\frac{4}{1})^{2}+(\frac{3}{1})^{2}\\ \\a=16+9\\ \\ a=25 \\\\  b=\frac{2.(\frac{1}{3})^{-1}-2^{2}}{(\frac{1}{2})^{-2}} \\ \\ b=\frac{2.(\frac{3}{1})^{1}-4 }{(\frac{2}{1} )^2} \\ \\ b=\frac{2.3-4}{4} \\ \\ b=\frac{6-4}{4} \\ \\ b=\frac{2}{4}\\ \\ a.b=25.\frac{2}{4} \\ \\ a.b=\frac{50}{4} \\ \\ a.b=12,5$

Alternativa c)